Talk:Coolout Conjecture
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The phrase "internally consistent with being part of a still life" is rather vague. I think it should be rephrased to make it clearer which patterns are or are not eligible. 77topaz (talk) 03:58, 31 January 2018 (UTC)
- There may not be sufficient documentation of the conjecture to determine this precisely. However, I believe the natural reading would be "every 3×3 area of the partial (or smaller, if overlapping with the partial's edges) is capable of occurring in a still life".
- Schroeppel's original counterexample, and its 5×2 version, suffice to disprove actually even a stronger condition of 4×4-consistency (their 4×2 left ends could be extended into a shillelagh and hook with tail respectively) or also e.g. range 2 von Neumann neighborhood consistency. --Tropylium (talk) 11:35, 15 July 2026 (UTC)
5×5 consistency seems to not have been disproven yet.If a partial is allowed to have indentations in it, we could craft examples of the sort shown on the left here, where the thickness-2 white/blue area with a П shape is the partial (green cells are casing). 5×5 overlaps with it can be stabilized (as shown on the right), but the whole thing cannot, since this would require both of the deep corner cells shown in yellow to be present.
x = 28, y = 6, rule = LifeHistory .A.A2.2A5.A.A2.A2.2A.A2.A$AB5CBA3.AB4CA2.A.5C$A7BA3.A5B5.5B$.CBE.EBC 5.CBEA6.B.A.B$ACBA.ABCA3.ACB2A6.BA.AB$4.A20.A!
- Anyway, having now had my coffee and following more closely on the tails of the original construction, here are a 8×2 partial that disproves 7×n consistency, a 11×2 partial that disproves 10×n consistency, and a 14×2 partial that disproves 13×n consistency:
x = 31, y = 27, rule = LifeHistory 16.A$15.A.A$15.A2.A$2CB2CB2C4.2CB2CBC$CBC2BCBC4.CBC2BCB$3.2A10.2A5$ 19.2A$18.A2.A2.2A$18.A2.A2.A$2CB2CB2CB2C4.2CB2CB2CBC$CBC2BC2BCBC4.CBC 2BC2BCB$3.A.A.A10.A.A.A$4.A.A12.A.A$5.A14.A3$22.2A4.A$21.A2.A2.A.A$ 21.A2.A2.A2.A$2CB2CB2CB2CB2C4.2CB2CB2CB2CBC$CBC2BC2BC2BCBC4.CBC2BC2BC 2BCB$3.A.A2.A.A10.A.A2.A.A$4.A4.A12.A4.A!