Automaton rule 30 pattern
Posted: September 27th, 2026, 6:22 pm
1
add non stationary 0
00100
Then divide to 3 digit each
00100
^^^
001
001100
__^^^
The carrot point to 011
001100
___^^^
The carrot point to 110
001100
____^^^
The carrot point to 100
001,010,100
then add value to each 3 digit,because the digit is 3 so the value is 3 so x=3 f(x)=x-1,stop in x=1
001:
321
the 0 occupy 3&2 value so
"0"=3+2=5
the 1 occupy 1 value
"1"=1
The first digit is 0 so "0"≥"1",5≥1=1
010:
321
"0"=3+1=4
"1"=2
"0"≥"1"=correct=1
100:
321
"1"=3
"0"=3
"1"≥"0" because 1 is the first digit,3≥3=correct=1
Then sum 1,1,1 so the next row is 111
For row 3
0011100
001:
321
"0"=5
"1"=1
"0"≥"1"=1(first digit is 0 so "0"≥"1")
011:
321
"0"=3
"1"=3
3≥3=1
111:
321
there's only 1 and no 0 so the result is 0
110:
321
"1"=3
"0"=1
"1"≥"0"=0(first digit is 1 so "1">"0")
100:
321
"1"=3
"0"=3
3≥3=1
So 1,1,0,0,1=11001
The result is
1
111
11001
Which match the rule 30
add non stationary 0
00100
Then divide to 3 digit each
00100
^^^
001
001100
__^^^
The carrot point to 011
001100
___^^^
The carrot point to 110
001100
____^^^
The carrot point to 100
001,010,100
then add value to each 3 digit,because the digit is 3 so the value is 3 so x=3 f(x)=x-1,stop in x=1
001:
321
the 0 occupy 3&2 value so
"0"=3+2=5
the 1 occupy 1 value
"1"=1
The first digit is 0 so "0"≥"1",5≥1=1
010:
321
"0"=3+1=4
"1"=2
"0"≥"1"=correct=1
100:
321
"1"=3
"0"=3
"1"≥"0" because 1 is the first digit,3≥3=correct=1
Then sum 1,1,1 so the next row is 111
For row 3
0011100
001:
321
"0"=5
"1"=1
"0"≥"1"=1(first digit is 0 so "0"≥"1")
011:
321
"0"=3
"1"=3
3≥3=1
111:
321
there's only 1 and no 0 so the result is 0
110:
321
"1"=3
"0"=1
"1"≥"0"=0(first digit is 1 so "1">"0")
100:
321
"1"=3
"0"=3
3≥3=1
So 1,1,0,0,1=11001
The result is
1
111
11001
Which match the rule 30