ConwayLife.com

Posted: **October 16th, 2021, 4:17 am**

x = 72, y = 12, rule = DoubleB3S23
43.2B$42.B.B$42.B$.2B8.2B9.2B7.2B8.2B.B6.2B11.B$B2AB6.B2AB7.B2AB5.B2A
B6.B2ABAB4.B2AB9.BAB$B2AB6.BABAB5.BA2BAB4.BABAB5.BAB2AB4.BABAB4.2B.BA
BAB.2B$.2B8.BAB7.B2AB6.B2AB6.B.2B6.BABAB.B2.B.BABAB.B2.B$12.B9.2B8.2B
9.B8.B2AB.2B2.B2AB2AB2.2B$41.B.B9.2B7.2B.2B$41.2B20.B.B$63.B.B$62.2B.
2B!

There are lots of SLs which contain smaller photonegative SLs inside. Presented are the (hopefully) minimal SLs for each contained SL with <= 10 bits that are possible.

Posted: **October 16th, 2021, 11:07 am**

pzq_alex wrote: October 16th, 2021, 4:17 am There are lots of SLs which contain smaller photonegative SLs inside. Presented are the (hopefully) minimal SLs for each contained SL with <= 10 bits that are possible.

That's interesting. I'm trying to understand if there's a reason to expect this, or if it's just a coincidence. The interior cells are overcrowded with either 4 or 5 live neighbors, so they have 3 or 4 empty neighbors, but one is outside the boundary and not counted as part of the negative. I can also see why tub and barge never appear as negatives (they would require a live cell in the original still life with 4 neighbors). The interior "live" negative cells are overcrowded and the ones around the boundary usually have 2 or fewer neighbors unless there's a stabilization.

Can these grow arbitrary large? Maybe in one direction like a snake.

Posted: **October 16th, 2021, 11:36 am**

Just dropping a quotation:

mniemiec wrote: May 5th, 2016, 12:25 pm The number of still-life interiors that this can be done with is extremely limited. It's easy to show that the interiors of tubs (including all barges, long boat, and very long ships), carrier, loaves, pythons, ponds, mangos, shillelaghs, loops, and anything with an eater tail are toxic. This can be done with snakes of any length, so there are infinitely many solutions. I could only find the following viable ones up to 10 bits (although many of these can be modified into alternates containing the same inverted still-lifes):
Code: Select all
x = 49, y = 78, rule = B3/S23
4boo$3bobbo$3bobbo$4boo7$4boo$3bobbo$3bobobo$4bobo$5bo3$43boo$43bobo$
45bo$5boo17boo18boobo$4bobbo15bobbo16bobbobo$3boboobo14bobobo15bobobbo
$4bobbo16bobbo16boboo$5boo18boo19bo$46bobo$47boo3$9boo$5boobbo$boobobb
obo$bobooboboboobo$5bobobboboo$5bobboo$4boo5$4boo19boo3boo$3bobbo14boo
bobbobbo$3bobobo13boboobobobo$4bobobo16boboboboobo$5bobbo16bobbobboboo
$6boo16boo3boo7$23boo$23bobo$25bo$4boo18booboo$oobobbo3boo11bobbobbo$o
boobobobbo8booboboboboboboo$4bobobobo8bobooboboboboobo$4bobboboboobo
10bobo$3boo3bobboboo11bo$9boo6$23boo$23bobo4boo$25bo4bo$4boo18booboobo
$oobobbo13boobobbobboboobo$oboobobo3boo7boboobobbobboboo$4bobobobbo12b
obooboo$4bobbobobo12bo4bo$3boo3boboboobo7boo4bobo$9bobboboo14boo$10boo!

Posted: **October 16th, 2021, 7:13 pm**

I've managed to show that all CGOL stilllived that have any of B4ceknyqjtz can't have a negative.

Posted: **September 8th, 2022, 1:48 pm**

Tails are possible, how did you think that it is impossible?

Code: Select all

x = 9, y = 7, rule = LifeHistory
.2A$A2DA$ADADA2.2A$.ADADA2.A$3.ADA.A$3.A2DA$4.2A!

My 550yh post!
Edit 1:
Oops, still missing a side. However, hat is possible and is dot with two tails
Edit 2:
Let's prove what erictom333 proved.
1:
B4c
Let's focus on the b4c place:

Code: Select all

x = 3, y = 3, rule = LifeHistory
CBC$3B$CBC!

In order for it to be b4c, the blue cells cannot be on. That means that there is s4e in the still life that contains that in the photonegative, which is impossible.
2:B4e
In a similar way, the blie cells cannot be on, meaning there is s4c in the still life that contains it in the photonegative

Code: Select all

x = 3, y = 3, rule = LifeHistory
BAB$ABA$BAB!

3:B4
The other cells in whatever B4 transitions(the blue cells) cannot be on, meaning teher is s4 in the still life that contains it in the photonegative.
How about b5?
4:B5y
Possible.

Code: Select all

x = 6, y = 5, rule = LifeHistory
2.2A$.A2DA$AD2ADA$.A2DA$2.2A!

5:B5c
Possible.

Code: Select all

x = 5, y = 5, rule = LifeHistory
2.A$.ADA$ADADA$.A2DA$2.2A!

6:
B5i
Impossible to have one because of overpopulation.

Posted: **September 9th, 2022, 10:07 pm**

the tubber just felt lonely...

Code: Select all

x = 141, y = 45, rule = LifeHistory
134.A.A$133.A.2A$120.A.A8.3A$119.A.2A7.A4.2A$106.A.A8.3A10.A2.2A2DA.2A
$105.A.2A7.A4.2A6.2A.A2.2DA.A$92.A.A8.3A10.A2.2A2.A.2A.A3.A3.A3.A$91.
A.2A7.A4.2A6.2A.A.2D.A.A3.A.A4.A.2A$78.A.A8.3A10.A2.2A2.A.2A.A3.AD.DA
3.A.2A.A2.2A2.A$77.A.2A7.A4.2A6.2A.A.D2.A.A3.A.A.2D.A.2A6.2A4.A$64.A.
A8.3A10.A2.2A2.A.2A.A3.AD.DA3.A.2A.A2.2A2.A10.3A$63.A.2A7.A4.2A6.2A.A
.D2.A.A3.A.A.2D.A.2A6.2A4.A7.2A.A$50.A.A8.3A10.A2.2AD.A.2A.A3.AD.DA3.
A.2A.A2.2A2.A10.3A8.A.A$49.A.2A7.A4.2A6.2A.A.D.DA.A3.A.A2.D.A.2A6.2A4.
A7.2A.A$36.A.A8.3A10.A2.2A2DA.2A.A3.AD.DA3.A.2A.A2.2A2.A10.3A8.A.A$35.
A.2A7.A4.2A6.2A.A.D.DA.A3.A.A2.D.A.2A6.2A4.A7.2A.A$22.A.A8.3A10.A2.2A
2DA.2A.A3.AD.DA3.A.2A.A2.2A2.A10.3A8.A.A$21.A.2A7.A4.2A6.2A.A.D.DA.A3.
A.A.2D.A.2A6.2A4.A7.2A.A$8.A.A8.3A10.A2.2A2DA.2A.A3.AD.DA3.A.2A.A2.2A
2.A10.3A8.A.A$7.A.2A7.A4.2A6.2A.A.D.DA.A3.A.A2.D.A.2A6.2A4.A7.2A.A$5.
3A10.A2.2AD.A.2A.A3.AD.DA3.A.2A.A2.2A2.A10.3A8.A.A$4.A4.2A6.2A.A.D.DA
.A3.A.AD.D.A.2A6.2A4.A7.2A.A$4.A2.2A2DA.2A.A3.AD.DA3.A.2A.A.D2A2.A10.
3A8.A.A$3.2A.A.D.DA.A3.A.AD.D.A.2A6.2A4.A7.2A.A$2.A3.AD.DA3.A.2A.A.D2A
2.A10.3A8.A.A$3.A.AD.D.A.2A6.2A4.A7.2A.A$2.2A.A2D2A2.A10.3A8.A.A$6.2A
4.A7.2A.A$9.3A8.A.A$6.2A.A$6.A.A2$6.A.A$5.A.2A$3.3A$2.A4.2A$2.A2.2A2D
A.2A$.2A.A3.DA.A$A3.AD.DA3.A$.A.AD3.A.2A$2A.A2D2A2.A$4.2A4.A$7.3A$4.2A
.A$4.A.A!

...

but it's sadly an oscillator so it's still lonely. it also has a photonegative bipole on the bottom.

ConwayLife.com

Photonegative inside

Photonegative inside

Re: Photonegative inside

Re: Photonegative inside

Re: Photonegative inside

Re: Photonegative inside

tubber's happy place