The F/I^2/G^2 Challenge
Posted: April 20th, 2021, 7:38 am
We all know that there it couldn't be cubic growth? Great.
So the biggest of F/G is quadratic growth. So this challenge uses 1/G^2.
Rules same as the Non-totalistic CA Growth ChallengeTheriotially max would be 2 if no b1e patterns found, I think
Edit1: This one by Moosey in the sandbox is 0.96(24/5^2/1^2)If B1e It's 5 with this partial impossible to complete:
2+(2x+1)/x^2 and if B1(which won't stabalize) It would be max 8
So the biggest of F/G is quadratic growth. So this challenge uses 1/G^2.
Rules same as the Non-totalistic CA Growth Challenge
So here for an example, a 5/1/4=1.25Rules:
1. The rule must be in the form of B/S, no custom ruletables, generations, or LTL
2. The pattern cannot be adjustable, so you cannot have a puffer colliding with another.
3. It is allowed for the final pattern to oscillate, just pick a random point in time or find the maximum population.
4. The pattern must stop growing at some point. Infinite growth patterns are not allowed.
Code: Select all
x = 3, y = 1, rule = B2ci/S03i4e
obo!Edit1: This one by Moosey in the sandbox is 0.96(24/5^2/1^2)
Code: Select all
x = 1, y = 1, rule = B1e2-an3ejkry4ejrw5ceny6c7c8/S2ik3-aejr4ceknqy5ej6e
o!Code: Select all
x = 1, y = 1, rule = B1e3a/S012345678
o!