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Minesweeper meets Life (puzzle)
Posted: July 5th, 2009, 6:39 am
by Macbi
I have a starting pattern. If I apply the rule S0/B2 I get this pattern:
If I apply the rule S01/B3 I get this pattern:
What pattern did I start with?
I think this puzzle is not too easy, not too hard. It has a unique answer.
Re: Minesweeper meets Life (puzzle)
Posted: July 5th, 2009, 6:57 am
by apg
The solution: (RLE encoded to avoid spoilers)
Code: Select all
x = 11, y = 8, rule = B3/S01
9bo$3bo4bo$3bo6bo$$ooboboo$$3bo$3bo!
I've encountered Minesweeper-like puzzles in Life when trying to stabilise still-lifes or
drifter searcher results.
Re: Minesweeper meets Life (puzzle)
Posted: July 8th, 2009, 1:08 am
by Extrementhusiast
A new puzzle:
B35/S24 with 2 gens:
Code: Select all
..O.O..
....O..
...OO..
O.OOOOO
....O.O
..OOOOO
...O.O.
...OO..
B36/S125 (2x2) with 3 gens:
Code: Select all
O.O...
O.....
....O.
.....O
......
OO...O
O...O.
O.....
O.O...
What did I start with?
Hint: The answer is three times the number that is midway between the two numbers, each of whom has a rectangle with that area and perimeter. Confused? The number 8, for instance, in a 2x4 rectangle, has area 8 but perimeter 12. A 2x2 rectangle has perimeter 8 but area 4. Find two rectangles where their perimeters equal their respective areas, note their numbers, add them up, then divide by two.
Further hint: (1=on, 0=off, code solutions into binary)
Code: Select all
4*7
5*4
7*3
11+6
37-8
x+x=x*x=solution
56/2
Re: Minesweeper meets Life (puzzle)
Posted: March 16th, 2021, 4:31 pm
by Macbi
Extrementhusiast wrote: July 8th, 2009, 1:08 amFurther hint: (1=on, 0=off, code solutions into binary)
Code: Select all
4*7
5*4
7*3
11+6
37-8
x+x=x*x=solution
56/2
That is a weird way to write a number.
Code: Select all
x = 5, y = 7, rule = B3/S23
3o$obo$obobo$o3bo$3obo$2bo$3o!