My number is larger [GAME]

[hotdogPi]

Starting slowly: 2 - 1.02^35

[Sarah]

1/10

[HotWheels9232]

1

[yujh]

pi-2^log(3)
I feel like I shouldn’t post in this thread, who knows

[confocaloid]

1+1/9381

[ihatecorderships]

sqrt(10)/ln(10)

[yujh]

pi-In(pi+e)

why not just move this to a discord server? This is gonna make too many new posts

Edit: yes to below, should have made it clearer.

[hotdogPi]

11/8 (assuming "log" in the previous post was the natural logarithm, since I'm pretty sure the intent was to beat it by the slightest bit)

[confocaloid]

5^(1/5)

[hotcrystal0]

Code: Select all

x = 12, y = 13, rule = B3/S23
2bo2b2o2bo$2bobo2bobo$2bo2b2o2bo$2bobo2bobo$2bo2b2o2bo2$12o2$bo2b2o3b
2o$bobo2bobo2bo$bo3bo2bo2bo$bo2bo3bo2bo$bob4o2b2o!

[hotdogPi]

π-φ

[NimbleRogue]

Code: Select all

x = 37, y = 21, rule = B3/S23
3$34bo$34bo$34bo$34bo$34bo2$27b3o2b5o2$32b5o$36bo$2bo23bo5b5o$bo5b3o
10b3o4bo4bo$bo4bo3bo8bo3bo3bo4b5o$bo3bo5bo2b3o2b5o3bo$bo3bo5bo7bo7bo$b
o3b3ob3o8b4o3bo$2bo23bo!

[hotdogPi]

Start with the numbers 7 and 11. The next number in the sequence is the closest integer where the most recent number (11 to begin) is the geometric mean of the new number and the previous number (7 to begin). The number played for this game is what the ratio of two successive terms approaches: 1.54993045...

(7 and 11 seems to be the lowest number pair where doing this doesn't form a recognizable sequence.)

This sequence is A21013 on OEIS.

[confocaloid]

The root of x^x=2 (1.55961046...)

[Moosey]

The integral from 0 to 4 of mod(1,mod(4,x)) dx (where mod(a,b) is the modulo operator). Approximately 1.59246343...

[hotdogPi]

I know there's an obvious number coming up, but I'll take ln(5) first.

[confocaloid]

Code: Select all

x = 159, y = 20, rule = B3/S23
9bob2o10bob2obob2obob2obob2obob2o$9b2obo10b2obob2obob2obob2obob2obo$
13b2o6b2o$14bo7bo$13bo7bo$13b2o6b2o$2o9b2o6b2o6b2obo6b2obo25b2o10bob2o
4b2obo6b2obo8bob2o2bob2o6b2obo6b2obo4b2o3b2o$o11bo7bo6bob2o6bob2o26bo
10b2obo4bob2o6bob2o8b2obo2b2obo6bob2o6bob2o4b2o3b2o$bo9bo7bo11b2o2b2o
4b2o23bo9b2o6b2o4b2o2b2o4b2o4b2o10b2o2b2o4b2o2b2o4b2o$2o9b2o6b2o10bo3b
o5bo24b2o7bobo6bo5bo3bo5bo4bobo11bo2bo5bo3bo5bo3b2o3b2o$2b2o5b2o6b2o
13bo3bo5bo7bob2obob2o16bo9bo5bo3bo5bo3bo12bo4bo5bo3bo5bo2bobobobo$2bo
7bo7bo12b2o2b2o4b2o7b2obob2obo7b2o6b2o8b2o4b2o2b2o4b2o2b2o12b2o2b2o4b
2o2b2o4b2o4bobo$3bo5bo7bo9b2obo6b2obo26bo8b2obo4bo5bo5b2obo6b2obo6b2o
4bo5bo3bo5bo4b2obo$2b2o5b2o6b2o8bob2o6bob2o25bo9bob2o5bo5bo4bob2o6bob
2o7bo5bo5bo3bo5bo7b2o$4b2o9b2o8b2o8b2o4b2o7bob2obob2o7b2o6b2o4b2o2b2o
4b2o8b2o2b2o4b2o4bo5b2o4b2o2b2o4b2o8bo$4bo11bo8bo9bo5bo8b2obob2obo15bo
5bo3bo5bo9bo3bo5bo5b2o4bo5bo3bo5bo8bo$5bo9bo10bo9bo5bo23b2o7bo5bo3bo5b
o9bo3bo5bo2b2o7bo5bo3bo5bo7b2o$4b2o9b2o8b2o8b2o4b2o24bo6b2o4b2o2b2o4b
2o8b2o2b2o4b2o3bo6b2o4b2o2b2o4b2o8bo$6b2obobob2o12b2obo6b2obo25bo3b2o
4b2obo6b2obo6b2obo6b2obo4bo9b2obo6b2obo9bo3b2ob2ob2o$6bob2ob2obo12bob
2o6bob2o25b2o2b2o4bob2o6bob2o6bob2o6bob2o4b2o8bob2o6bob2o9b2o2b2ob2ob
2o!

[Anivec]

φ

[NimbleRogue]

root(e)

[toroidalet]

6/sinh(2) (difference from last number ~=.0056)

[HotWheels9232]

Log(Period of twin bees shuttle)

[hotdogPi]

Image source: https://upgradedpoints.com/credit-cards ... s-program/

[Moosey]

(a slight increase in pace, I suppose) 7/4

[toroidalet]

(3√5+3√6)/2 (these are cube roots)
Difference ~= .0135

[squareroot12621]

$\frac{16}{9}.$
($+0.01423$)

Edit: Whoops. LaTeX doesn't work here, so I'll just write it out.
16/9. (+0.01423)