My number is larger [GAME]

[hotdogPi]

26sin(1)/9 ≈ 2.43091618 (+0.000138864514)

[radians]

[rutabaga]

log_9(91) + sqrt(1/7) = 2.43094510733 (+0.000028928992)

[CARuler]

RAYO(RAYO(.....{×RAYO}RAYO(RAYO))

[hotdogPi]

9cos(1)/2 ≈ 2.43136038 (+0.00041527267)

[again, radians]

[eRroR_6o6]

9((x^x)+x)=100

x is about 2.4317837983 to 10 decimal places (+0.000423421893371) (3 zeros, nice)

also I'm in both "my number is larger" threads and I can definitely tell you that this one is at least civilized

[confocaloid]

9((x^x)+x)=100

x is about 2.4317837983 to 10 decimal places (+0.000423421893371) (3 zeros, nice)

(2289 + 955) / (2289 - 955) ~ 2.4317841079...

[hotdogPi]

√(106/9)-1 ≈ 2.4318767137 (+0.00009260571631)

[Antonin Duda]

3.47^(5/7) = 2.431921906630056010802... (+0.0000451929677225722)

[CARuler]

3.47^(5/7)+(TREE(3)+1)/TREE(3)-1
(+1/TREE(3))
edit oops

[get_Snacked]

3.47^(5/7)+(TREE(3)+1)/TREE(3)
(+1/TREE(3))

(TREE(3)+1)/TREE(3) = 1+1/TREE(3), not 1/TREE(3)
so that is:
(+1+1/TREE(3))

[rutabaga]

3.47^(5/7)+(TREE(3)+1)/TREE(3)
(+1/TREE(3))

(TREE(3)+1)/TREE(3) = 1+1/TREE(3), not 1/TREE(3)
so that is:
(+1+1/TREE(3))

No. The 1 gets divided too, you can't just divide the TREE(3) and keep the other 1. Let's represent really small numbers (1/TREE(3) in this case) as q right now: [edit: I misunderstood what you wrote but I think we're saying the same thing here]
(TREE(3)+1)/TREE(3) + 1/TREE(3) = 1+2q
Hence:
3.47^(5/7)+(TREE(3)+1)/TREE(3) (+1/TREE(3)) is approximately 3.4319219066... which is WAY too large of a jump for this thread.
My number is (12.04 + (.03^2))^(5/14) + 1/SCG(13). Since 1/SCG(13) is practically zero, and the rest of my expression simplifies to the previous valid number, then mine is ever-so-slightly bigger than the last one.

Of course, this isn't allowed, so I'll actually go with:
ln(8.735 + sqrt7) = 2.43192344682 (+0.000001540193)

[Antonin Duda]

ln(8.735 + sqrt7) = 2.43192344682 (+0.000001540193)

log_pi(sqrt(261.8555555555555...)) ~ 2.43192438054 (+0.00000093372)

[hotdogPi]

5.6/ln(10) ≈ 2.4320490987 (+0.000124718118)

[C_R_116]

(462+115π-30π^2)/69π ≈ 2.432049098684 (+2.61017874E-11)

[confocaloid]

(462+115π-30π^2)/69π ≈ 2.432049098684 (+2.61017874E-11)

√√√n ≈ 2.4320509966079,
where n = u v (u + v),
where u = a^b, v = b^a,
where a = 2, b = 3.

[hotdogPi]

11.2^(1/e) ≈ 2.4321241484 (+.0000731518332)

[confocaloid]

(2 x 3 x 53 x 103 / 11) ^ (1/9) ≈ 2.4321241490 (approx. + 5.657237523965651e-10)

[hotdogPi]

(17+√13)/(2φ³) ≈ 2.43215541 (+.0000312584266)

[eRroR_6o6]

log_(pi^pi)((e^e^e)-(pi^pi))*y, where y is the Euler-Mascheroni constant, is approximately equal to 2.43231457948. (+0.000159172047005)

[confocaloid]

log_(pi^pi)((e^e^e)-(pi^pi))*y, where y is the Euler-Mascheroni constant, is approximately equal to 2.43231457948. (+0.000159172047005)

Code: Select all

1 + 17 * 38
-----------  ~ 2.432330827
0 +  7 * 38

[CARuler]

log_(pi^pi)((e^e^e)-(pi^pi))*y, where y is the Euler-Mascheroni constant, is approximately equal to 2.43231457948. (+0.000159172047005)

Are you sure?
https://en.m.wikipedia.org/wiki/Euler%27s_constant

[confocaloid]

log_(pi^pi)((e^e^e)-(pi^pi))*y, where y is the Euler-Mascheroni constant, is approximately equal to 2.43231457948. (+0.000159172047005)

Are you sure?
https://en.m.wikipedia.org/wiki/Euler%27s_constant

I checked that expression by eRroR_6o6 before posting my reply above and got a slightly different result, presumably due to accumulated error in one or both of computations. However, this is insignificant for this game, because eRroR_6o6's number remains larger than hotdogPi's number, and my number remains larger than eRroR_6o6's number.

Code: Select all

2.432314558428849

                                         %e
                                       %e        %pi
                          %gamma log(%e     - %pi   )
                          ---------------------------
                                 %pi log(%pi)

[hotdogPi]

confocaloid December 14 was the most recent play, right?

2+√3/4 ≈ 2.4330127019 (+0.0006818748246)

[rutabaga]

ln(10ln(pi))=2.43775379461 (+0.00474109272)

[rattlesnake]

800/(9*pi^pi) (roughly 2.437839, larger by 8.55941e-5