Roommates

For discussion of other cellular automata.
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635318657
Posts: 39
Joined: June 19th, 2020, 9:48 pm

Roommates

Post by 635318657 »

Here's Roommates, a 3-state outer-totalistic von Neumann neighborhood rule that I invented:

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x = 0, y = 0, rule = Roommates
!
@RULE Roommates
@TABLE
n_states:3
neighborhood:vonNeumann
symmetries:permute
var a = {0,1,2}
var b = a
var c = a
var d = a
var e = a
0,1,1,0,0,1
0,2,0,0,0,1
1,1,1,0,0,2
1,2,0,0,0,2
2,1,0,0,0,2
2,1,1,0,0,2
2,2,0,0,0,2
a,b,c,d,e,0
This rule is very active but nowhere near explosive. Here's a two-cell 165-gen methuselah:

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x = 2, y = 1, rule = Roommates
BA!
Ash can burn for a long time. Here's a 1616-gen methuselah to illustrate this:

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x = 9, y = 11, rule = Roommates
8.B10$BA!
Here’s a 3c/10d failedrep:

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x = 3, y = 1, rule = Roommates
ABA!
This rule contains six common oscillators:

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x = 51, y = 7, rule = Roommates
37.A$38.A$A8.A8.A.A5.2A11.A$.A6.A.A6.A7.AB.A5.A5.A8.2B$9.A8.A.A6.B7.A
13.AB$36.A$37.A!
These oscillators can interact in various ways.

This rule, unfortunately, has no known spaceships.

One interesting thing about this rule is how it can form long "tails" of ash expanding far outside the original bounding box, like in the following soup:

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x = 31, y = 31, rule = Roommates
2A.A.6A.6A4.2A.A.A.2A$3A11.A3.2A4.3A3.A$2.3A2.5A.3A2.2A2.3A5.A$4A.2A.
A3.A5.A2.A2.3A.A.A$.2A.A.A2.2A7.2A2.2A$3A.A4.A5.2A.2A.2A2.2A$.2A.A2.2A
.A2.2A2.A.2A.2A.A.2A$4A3.A.A.4A3.A.3A.3A2.A$A.A3.2A.A2.2A3.3A3.3A.3A$
7.4A.3A.A.2A4.A.2A$.2A.3A.2A3.A3.4A.3A.A.3A$.2A3.A.3A.2A2.A2.3A.2A.3A
.A$.2A2.A.4A3.A.4A6.4A$.A.4A.2A.A.2A3.4A3.4A$.5A3.A4.3A6.2A.2A.2A$2.2A
.A2.A.A.A.A2.3A.A.2A.2A.2A$.2A13.A3.5A.A.A.A$4A2.A7.A.2A2.A4.2A2.2A$2A
.A.5A5.8A3.4A$3.A4.3A3.2A.A4.A.A.A.2A$A3.3A.A3.A.3A3.A4.2A3.A$2A.10A2.
3A.4A5.3A$3A4.2A.2A2.A.2A2.9A.A$3.A3.4A3.3A.A2.3A.A2.A$2.A2.2A2.A.A.4A
3.A2.A.A.3A$A2.2A.2A3.A2.5A.A3.3A.A.A$3A.A2.A5.2A4.A3.2A.A.3A$.A5.A.2A
2.A.A.2A6.2A2.A$A.2A2.3A2.A.3A.2A2.3A.2A2.2A$.2A4.2A3.A.3A2.3A4.A2.2A
$3A2.A.A.3A3.4A3.3A.A2.2A!

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x = 68, y = 3, rule = B2e3-ckqy4rz5r/S2-n3eijry5i6a
14bo25b2o10bo12b2o$3o10b3o10b3o10bobo10b2o11b2o$obo10bobo11bo13bo11b2o
10b3o!
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pifricted
Posts: 1116
Joined: May 25th, 2024, 10:26 am
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Re: Roommates

Post by pifricted »

635318657 wrote: August 8th, 2024, 7:38 pm This rule, unfortunately, has no known spaceships.
Vn neibourhood rules are hard to get a spaceship, because it's hard to get a c/2 move.

I have a c/3 move:

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x = 5, y = 9, rule = VNline2
3A$5B$3A4$3.A$2.2BA$2.BA!
Also, There're five Vn 3 state OT rule have spaceship:
VnLine2 (see above)
pifricted wrote: July 27th, 2024, 6:21 am Have to triple post. :(

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#c/6o
x = 7, y = 3, rule = vNtest
3.B$A5BA$2.3B!
@RULE vNtest
@TABLE
n_states:3
neighborhood:vonNeumann
symmetries:permute
var a={0,1,2}
var s=a
var d=a
var f=a
var q={1,2}
var w=q
var e=q
var r=q
0,2,0,0,0,1
0,1,1,0,0,1
1,1,1,0,0,2
a,q,w,e,a,2
q,w,e,0,0,0
1,a,0,0,0,0

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x = 20, y = 20, rule = VictoryVN
B2.2B.5B.A2.2A.2B$2A2B2.AB2.A.A2.BABAB$2BA4B2.A2.B.BA.BAB$2.B.2A.B.A.
A.B3.A$B2A.B2.AB2.2B.2A.B.A$.AB4.2BA2B.B2.B2.A$4.B2.B.3A2.B2.A$AB.B3.
B2.B.4A2.A$2.B.B.2A5.A2.4A$2.B.A.A2B.B.A2.2A2B$2.AB2.2A.BA.BAB2.3B$AB
.3A.2BAB.3B.A.A$A.BA.B3.A.A.2A2.2BA$5.AB2A2.2AB2.B.2A$A2.AB3.2A.A2.AB
.B.B$A2.A.2A.A.A.2B5.B$5.A.AB3.A.B4.A$B5.4B2A2B.A$.B.BA8.A2B2.A$3.A.B
3.A.B.BA.3BA!

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x = 20, y = 20, rule = V3k4 mphi
B2ABAB.B6.B.B.B$BA.B.A2.B.B2A2BA.3B$A.2B2A3.B4.3ABA$ABAB.A.2B2A.BAB.A
.A$6.B.B.B.2B2.B$2B2A.B8.B.A2.A$A.ABA.A2B.BA3.B2A.A$3.A.A2.ABAB2A2.BA
.A$.BAB4A.A2B.B5.B$2BA.BA3B3.2B.A.B.B$3A2.AB7.B.3AB$.A3B3A2.BA.AB.2A.
A$2B2.A2.AB.A.A2.A.A$.A.4A2.2B2.B.A.A$2.A6.BA3.B.B.2A$B2.2B2.A.2A.A3.
A.BA$5BA.BA.A2.ABA.BA$BA.B2.2A.B.2B.B3.B$B4.AB.2BA2.B4.B$B.B2A2.B2.2B
.2B2.2A!

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x = 20, y = 20, rule = V3k4 202200222012210V
B2ABAB.B6.B.B.B$BA.B.A2.B.B2A2BA.3B$A.2B2A3.B4.3ABA$ABAB.A.2B2A.BAB.A
.A$6.B.B.B.2B2.B$2B2A.B8.B.A2.A$A.ABA.A2B.BA3.B2A.A$3.A.A2.ABAB2A2.BA
.A$.BAB4A.A2B.B5.B$2BA.BA3B3.2B.A.B.B$3A2.AB7.B.3AB$.A3B3A2.BA.AB.2A.
A$2B2.A2.AB.A.A2.A.A$.A.4A2.2B2.B.A.A$2.A6.BA3.B.B.2A$B2.2B2.A.2A.A3.
A.BA$5BA.BA.A2.ABA.BA$BA.B2.2A.B.2B.B3.B$B4.AB.2BA2.B4.B$B.B2A2.B2.2B
.2B2.2A!
(All of them have B1 or B2 part, aren't they?)
...is enjoying his teenage time.
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