My number is larger [GAME]

[hotdogPi]

2

[yujh]

pi^(2pi/10) = 2.05290322778

[hotdogPi]

What's with the large jumps recently?

φ^(3/2) = 2.05817103

[squareroot12621]

4 – π/φ ≈ 2.058389. (+0.000218)

[toroidalet]

(33/23)^2 = 2.058601 (+.0021217)

I'm a bit concerned that the integers involved are too large.

[Moosey]

I feel like the game works much better the way we've done it. Restricting it to integers makes it pointless.

well, the original idea was to eventually get to enormous (i.e. googological) numbers. Though as it's been going right now is fine as well imo.

Btw:

π-√(5/8)=1.8766815 (+.0001386)
Who will be the first to get 4 leading 0s?

I'm getting about 2.351, not 1.877, for this.

Also btw, my play will be 2+(53^52/52^53)^0.95 = 2.060043 (+0.00144148...), because I think this is #53

[hotdogPi]

I'm getting about 2.351, not 1.877, for this.

8/5 instead of 5/8 gives the correct number.

[squareroot12621]

sqrt(316)-sqrt(247)≈2.060155.

[yujh]

sqrt(pi+3/e) ≈ 2.0603958302

[pzq_alex]

tan(pi * log_7(2)) = 2.06100166352446...

Code: Select all

$ ./ries 2.061 -x -s --one-sided

   Your target value: T = 2.061                                  mrob.com/ries

     x = ln(8)                               for x = 2.07944154167984      {47}
     x = 1/ln(phi)                           for x = 2.07808692123503      {53}
     x = e"/7                                for x = 2.04594613090996      {56}
     x = (pi"/pi)^2                          for x = 2.07250429282447      {59}
     x = (1+pi)/2                            for x = 2.0707963267949       {61}
     x = atan2(6,-pi)                        for x = 2.05314423389592      {63}
     x = sqrt(phi)^3                         for x = 2.05817102727149      {63}
     x = 1/4^2+2                             for x = 2.0625                {64}
     x = sqrt(3 sqrt(2))                     for x = 2.05976714390712      {65}
     x = phi/atan2(1)                        for x = 2.06014485920194      {67}
     x = sqrt(1/4+4)                         for x = 2.06155281280883      {67}
     x = sqrt(e^2-pi)                        for x = 2.06093751611757      {68}
     x = tanpi(log_7(2))                     for x = 2.06100166352446      {71}
                  (for more results, use the option '-l3')

  atan2(y,x) = Angle of ray from origin through point (y,x)  pi = 3.14159...
  log_A(B) = logarithm to base A of B = ln(B) / ln(A)  tanpi(X) = tan(pi * x)
  e = base of natural logarithms, 2.71828...  sqrt(x) = square root
  ln(x) = natural logarithm or log base e  A"/B = Ath root of B
  phi = the golden ratio, (1+sqrt(5))/2

                         --LHS--      --RHS--      -Total-
     max complexity:          15           63           78
          dead-ends:          77      7819251      7819328  Time: 0.507
        expressions:           1       520036       520037
           distinct:           1       163176       163177  Memory: 11520KiB

        Total equations tested:                  163176 (1.632e+05)
        

[squareroot12621]

101/49 ≈ 2.06122. (+0.000223)

[NimbleRogue]

φ^φ-1/(𝜋e)≈2.061357904886... (+0.000133)

[Wyirm]

1+1/10phi = 2.06180339887 (+0.000445493986028)

[squareroot12621]

33/16 = 2.0625. (+0.000697)

[Moosey]

76e/100 = 2.065894...

1+1/10phi = 2.06180339887 (+0.000445493986028)

I'm assuming you meant 2+1/(10phi) here.

[hotdogPi]

e*tanh(1) = 2.07022755 (+0.00433336037)

[HotWheels9232]

Lock this thread not CA-related and generates a lot of posts.

[Smurf]

Lock this thread not CA-related and generates a lot of posts.

It's in the sandbox, so it should still be unlocked.

[HotWheels9232]

Lock this thread not CA-related and generates a lot of posts.

It's in the sandbox, so it should still be unlocked.

No it isn't, or why did nobody play word chains but someone plays Cellular automata only word chains?

[get_Snacked]

this is boring, but since i don't want to waste my time coming up with a cool formula, i choose 2.08.

[HotWheels9232]

this is boring, but since i don't want to waste my time coming up with a cool formula, i choose 2.08.

2.8+1/G(1)
My 1000000101th post!
Also, lock this tread

[get_Snacked]

why should this thread be locked? i know from other posts you have that you think this does not relate to CA, but this is the sandbox! why would pzq_alex's random posts not be locked, then? mathematics are also a substantial part of understanding cellular automata.

[hotcrystal0]

sqrt(5)/2+1 (about 2.11803...)

[pipsqueek]

2+(sqrt(2)-1)/3+sqrt(1/137) ≈ 2.2235069

[squareroot12621]

sqrt(5) ≈ 2.23607. (+0.01256)