ConwayLife.com

Sorry, I worded that very badly. What I meant to say was that I think I may have found a pattern that cannot be destroyed by **two gliders**, but I failed to include the word "two" in my post.

Also, by "destroyed" I didn't mean that an individual glider collision has to leave the pattern unchanged ...

I checked a bit more, and I think even a somewhat smaller version may still resist all the glider collisions I've tried. What do you think?

x = 28, y = 28, rule = B3/S23
13b2o$12bo2bo$12bo2bo$10b2ob2ob2o$9bo2bo2bo2bo$9bo2bo2bo2bo$7b2ob2ob2o
b2ob2o$6bo2bo2bo2bo2bo2bo$6bo2bo2bo2bo2bo2bo ...

I've tried quite a lot of different glider collisions against this pattern, and so far I haven't found one that destroys it. Does anyone see an obvious way to break it?

It's not exactly a small pattern, though.

x = 118, y = 118, rule = B3/S23
58b2o$57bo2bo$57bo2bo$55b2ob2ob2o$54bo2bo2bo2bo ...

I may have found a finite stable constellation that requires exactly three gliders for clean destruction. I haven't been able to find a previous construction of this kind, but I may have missed one.

The target consists of three widely separated blocks, with origins at


(0, 0)
(100000, 300000 ...

I think this still life cannot be destroyed with 2 gliders, but I am not quite sure.
x = 91, y = 91, rule = B3/S23
bo$obo$bobo$2bobo$3bobo$4bobo$5bobo$6bobo$7bobo$8bobo$9bobo$10bobo$11b
obo$12bobo$13bobo$14bobo$15bobo$16bobo$17bobo$18bobo$19bobo$20bobo$21b
obo$22bobo$23bobo$24bobo$25bobo$26bobo ...